Various questions about the Kelvin wave angle: I looked in a book _Fluid Dynamics for Physicists_, by T E Faber. As John Winters suggested, it's geometric. It depends on the "dispersion relation" for gravity waves, i.e. wavelength being proportional to the square of the frequency. This is true when wave amplitude is small, water is deep, and wave length is large enough (much greater than an inch or so ( a few cm.)) that viscosity can be neglected. Also, as John said, it's based on a point source: the object creating the wave is very small. In practise, the waves created by each point on the hull add together. My guess is that finite wave amplitude is the major reason for departure from the ideal angle. Hope this helps, Bruce Bruce Winterbon bwinterb_at_magma.ca http://magma.ca:80/~bwinterb Capitalism means the greatest goods for the greediest. *************************************************************************** PaddleWise Paddling Mailing List - All postings copyright the author and not to be reproduced/forwarded outside PaddleWise without author's permission Submissions: PaddleWise_at_PaddleWise.net Subscriptions: PaddleWise-request_at_PaddleWise.net Website: http://www.paddlewise.net/ ***************************************************************************Received on Tue Oct 10 2000 - 05:17:47 PDT
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