On 11 Apr 2005 at 13:08, Dave Kruger wrote: > That gave me a chuckle! I have not done the complete calculation, but > I bet I'd have to be a lot buffer to get the equivalent of 1400 mAh > out of my arm in three minutes! If it's 7.2v (pretty typical of VHF radios), then that's 1.4*7.2 = 10.08 watt-hours = 605 watt-minutes. To do that in 3 minutes is 604/3 = 201 watts or about 0.27hp. That's about maximum paddling arm power for three minutes. Phew! More if the crank is less than 100% efficient. Charging voltages are higher and losses are not trivial (though small), so it's likely more like 0.4hp. How about a partial recharge instead? :-) Mike *************************************************************************** PaddleWise Paddling Mailing List - Any opinions or suggestions expressed here are solely those of the writer(s). You must assume the entire responsibility for reliance upon them. All postings copyright the author. Submissions: PaddleWise_at_PaddleWise.net Subscriptions: PaddleWise-request_at_PaddleWise.net Website: http://www.paddlewise.net/ ***************************************************************************Received on Mon Apr 11 2005 - 13:43:22 PDT
This archive was generated by hypermail 2.4.0 : Thu Aug 21 2025 - 16:31:20 PDT