After chewing on the swim versus stay with boat question, and how the decision affects survival, it occurs that a 2 by 2 contingency table analysis would give a nice statistical summary. Create the 4=2x2 cells as follows: row one is survivors, row two is non-survivors, column one is people who swam for it, column two is those who stayed with the boat. So in the 11-cell we have the number who survived and swam, in the 12-cell we have the number who survived and stayed with the boat, etc. If we had the cell counts C11, C12, C21, C22, we could do a chi-square test (with 1 df) of independence of rows and columns. If the hypothesis of independence of rows and columns is supported, then the conclusion would be that probability of survival is the same for swimmers and those who stayed with the boat. If sample size is too small to do a chi-square test, we could still use Fisher's Exact Test. Maybe you'd rather hear a joke. Rodney Dangerfield, who passed away recently, was looking at his calendar one day. All of a sudden it hit him like a ton of bricks. His days were numbered. BRC *************************************************************************** PaddleWise Paddling Mailing List - Any opinions or suggestions expressed here are solely those of the writer(s). You must assume the entire responsibility for reliance upon them. All postings copyright the author. Submissions: PaddleWise_at_PaddleWise.net Subscriptions: PaddleWise-request_at_PaddleWise.net Website: http://www.paddlewise.net/ ***************************************************************************Received on Mon Nov 12 2007 - 12:58:46 PST
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